std::enable_if
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Déclaré dans l'en-tête <type_traits>
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template< bool B, class T = void > struct enable_if; |
(depuis C++11) | |
Si
B
est true, std::enable_if a une type
membre du public typedef, égale à T
, sinon, il n'y a aucun membre typedef . Original:
If
B
is true, std::enable_if has a public member typedef type
, equal to T
; otherwise, there is no member typedef. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Cette métafonction est utilisée de façon conditionnelle pour supprimer les fonctions et les classes de la résolution de surcharge basée sur les caractères morphologiques et de fournir des surcharges de fonction séparées et spécialisations pour les caractères de type différents. std::enable_if peut être utilisé comme un argument de fonction supplémentaire (non applicable aux surcharges d'opérateur), comme type de retour (ne s'applique pas aux constructeurs et destructeurs), ou comme un modèle de classe ou d'un paramètre de modèle de fonction .
Original:
This metafunction is used to conditionally remove functions and classes from overload resolution based on type traits and to provide separate function overloads and specializations for different type traits. std::enable_if can be used as an additional function argument (not applicable to operator overloads), as a return type (not applicable to constructors and destructors), or as a class template or function template parameter.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Sommaire |
[modifier] Types de membres
Type d'
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
type
|
T supporte ou non tel élément, en fonction de la valeur de B Original: either T or no such member, depending on the value of B The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[modifier] Mise en œuvre possible
template<bool B, class T = void> struct enable_if {}; template<class T> struct enable_if<true, T> { typedef T type; }; |
[modifier] Exemple
#include <type_traits> #include <iostream> // foo1 overloads are enabled via the return type template<class T> typename std::enable_if<std::is_floating_point<T>::value, T>::type foo1(T t) { std::cout << "foo1: float\n"; return t; } template<class T> typename std::enable_if<std::is_integral<T>::value, T>::type foo1(T t) { std::cout << "foo1: int\n"; return t; } // foo2 overload is enabled via a parameter template<class T> T foo2(T t, typename std::enable_if<std::is_integral<T>::value >::type* = 0) { return t; } // foo3 overload is enabled via a template parameter template<class T , class = typename std::enable_if<std::is_integral<T>::value>::type > T foo3(T t) // note, function signature is unmodified { return t; } // A is enabled via a template parameter template<class T, class Enable = void> class A; // undefined template<class T> class A<T, typename std::enable_if<std::is_floating_point<T>::value >::type> { }; int main() { foo1(1.2); // OK, calls the first version of foo1() foo1(10); // OK, calls the second version of foo1() // foo2(0.1); // compile-time error foo2(7); // OK // A<int> a1; // compile-time error A<double> a1; // OK }
Résultat :
foo1: float foo1: int