GO concatenate string with int

Question

I’ve the following code which needs to get int value and add it to a string with string suffix. E.g.

At start I'm getting this

"fds data "

After the if statement it should like this

"fds data 10 M"

This is the code:

ltrCfg := "fds data "
if len(cfg.ltrSharedDicts) > 0 {
    ltrCfg += strconv.Itoa(cfg.ltrSharedDicts["c_data"])
    ltrCfg += "M"
} else {
    ltrCfg += "10M"
}
out = append(out, ltrCfg)

ltrCert := “fds data "
if len(cfg.ltrSharedDicts) > 0 {
    ltrCert += strconv.Itoa(cfg.ltrSharedDicts["d_data"])
    ltrCert += "M"
} else {
    ltrCert += “20M"
}
out = append(out, ltrCert)

The code is working but I wonder for the first fork of the if statement

if len(cfg.ltrSharedDicts) > 0 {
    ltrCfg += strconv.Itoa(cfg.ltrSharedDicts["c_data"])
    ltrCfg += "M"

Is there a better way to achieve it?

fmt.Sprintf will be much simpler, no?
– Not_a_Golfer
Commented Jun 23, 2019 at 10:50 — Not_a_Golfer, Commented Jun 23, 2019 at 10:50
I'd use fmt.Sprintf to do this kind of thing
– Vorsprung
Commented Jun 23, 2019 at 13:35 — Vorsprung, Commented Jun 23, 2019 at 13:35

peterSO · Accepted Answer · 2019-06-23 11:02:41Z

1

For readability, I would write:

cd, ok := cfg.ltrSharedDicts["c_data"]
if !ok {
    cd = 10
}
out = append(out, fmt.Sprintf("fds data %dM", cd))

edited Jun 23, 2019 at 11:02

answered Jun 23, 2019 at 10:54

peterSO

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Thanks, sorry but I didnt understand the if ? sometimes it should get hardcoded value, you can see that on the else..
– NSS
Commented Jun 23, 2019 at 11:43
1

@NinaS: If the map doesn't contain a value for "c_data" (!ok) then use the default value (10). "The value of ok is true if the key x is present in the map, and false otherwise.": golang.org/ref/spec#Index_expressions
– peterSO
Commented Jun 23, 2019 at 11:53

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