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    $\begingroup$ Why is 9 in your examples when the digits are 1, 8, 4, and 6? Also, is the order constrained? This doesn't feel like a riddle, and the rules are kind of vague… $\endgroup$
    – Someone
    Commented Nov 7, 2023 at 0:24
  • 1
    $\begingroup$ What about square roots with the order of digits? Can I do $\sqrt{1+8}$? The order in the title does not match the order in the body. What is the correct order? Please make your examples apply, so $21$ does not consist of allowable digits. $\endgroup$
    – Ross Millikan
    Commented Nov 7, 2023 at 3:20