Added problem_38 folder with solution file sol.py. TheAlgorithms#2695

Added problem_38 in project_euler TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: TheAlgorithms#2695

Name: Prime square remainders

Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and
let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2.

For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25.
The least value of n for which the remainder first exceeds 10^9 is 7037.

Find the least value of n for which the remainder first exceeds 10^10.

Reference: https://projecteuler.net/problem=123

reference: TheAlgorithms#2695

Name: Palindromic sums

The palindromic number 595 is interesting because it can be written as
the sum of consecutive squares: 6^2 + 7^2 + 8^2 + 9^2 + 10^2 + 11^2 + 12^2.
There are exactly eleven palindromes below one-thousand that can be written as
consecutive square sums, and the sum of these palindromes is 4164.

Note that 1 = 0^2 + 1^2 has not been included as this problem is concerned with
the squares of positive integers.

Find the sum of all the numbers less than 10^8
that are both palindromic and can be written as the sum of consecutive squares.

Reference: https://projecteuler.net/problem=125

Fixes: TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: TheAlgorithms#2695

Name: Prime square remainders

Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and
let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2.

For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25.
The least value of n for which the remainder first exceeds 10^9 is 7037.

Find the least value of n for which the remainder first exceeds 10^10.

Reference: https://projecteuler.net/problem=123

reference: TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: TheAlgorithms#2695

Name: Digit power sum

Problem Statement: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 83 = 512. Another example of a number with this property is 614656 = 284.
We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum.
You are given that a2 = 512 and a10 = 614656.
Find a30

Reference: https://projecteuler.net/problem=119

reference: #2695

Co-authored-by: Ravi Kandasamy Sundaram <rkandasamysundaram@luxoft.com>

Name: Divisor Square Sum

For a positive integer n, let σ2(n) be the sum of the squares of its divisors.
For example, σ2(10) = 1 + 4 + 25 + 100 = 130.

Find the sum of all n, 0 < n < 64,000,000 such that σ2(n) is a perfect square.

reference: TheAlgorithms#2695

Name: Divisor Square Sum

For a positive integer n, let σ2(n) be the sum of the squares of its divisors.
For example, σ2(10) = 1 + 4 + 25 + 100 = 130.

Find the sum of all n, 0 < n < 64,000,000 such that σ2(n) is a perfect square.

reference: TheAlgorithms#2695

Name: Prime square remainders

Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and
let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2.

For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25.
The least value of n for which the remainder first exceeds 10^9 is 7037.

Find the least value of n for which the remainder first exceeds 10^10.

Reference: https://projecteuler.net/problem=123

reference: TheAlgorithms#2695

Name: Divisor Square Sum

For a positive integer n, let σ2(n) be the sum of the squares of its divisors.
For example, σ2(10) = 1 + 4 + 25 + 100 = 130.

Find the sum of all n, 0 < n < 64,000,000 such that σ2(n) is a perfect square.

reference: TheAlgorithms#2695