util: remove unused fast path in internal debuglog

The internal `debuglog()` is never called with 0 parameters. Remove the fast-path for that situation. If it ever occurs, it will fall through to the default path. PR-URL: #41605 Reviewed-By: Anna Henningsen <anna@addaleax.net> Reviewed-By: Michaël Zasso <targos@protonmail.com>
nodejs · Jan 24, 2022 · 2b082def2e81537c71bb730b324fa26f1164df59 · 2b082de
1 parent 4b174ce
commit 2b082def2e81537c71bb730b324fa26f1164df59
Showing with 0 additions and 2 deletions.

+0 −2 lib/internal/util/debuglog.js
diff --git a/lib/internal/util/debuglog.js b/lib/internal/util/debuglog.js
@@ -81,7 +81,6 @@ function debuglog(set, cb) {
     if (typeof cb === 'function')
       cb(debug);
     switch (args.length) {
-      case 0: return debug();
       case 1: return debug(args[0]);
       case 2: return debug(args[0], args[1]);
       default: return debug(...new SafeArrayIterator(args));
@@ -95,7 +94,6 @@ function debuglog(set, cb) {
   };
   const logger = (...args) => {
     switch (args.length) {
-      case 0: return debug();
       case 1: return debug(args[0]);
       case 2: return debug(args[0], args[1]);
       default: return debug(...new SafeArrayIterator(args));