Differentiate undefined and null in useRouteQuery #2914
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I'm also confused by this. How do you set a querystring parameter without a value? |
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#3294 has been merged, so I think we can end the discussion here :) |
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I would like to differentiate these URLs:
/foo
/foo?q
/foo?q=bar
If I'm using
const route = useRoute()
that's possible;route.query.q === undefined
route.query.q === null
route.query.q === 'bar'
But with
const q = useRouteQuery('q')
there seems no differentiation betweenundefined
andnull
.q === null
q === null
q === 'bar'
Is that intentional? Did I miss an obvious solution?
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