Hello,

I have a piece of code that reacts to a TimeoutException, I want to test this code path. This code is also only checking for the status code to be 200. Here is a summary of my code as a test:

public function testTimeout(): void
{
    $responses = [ /* A timeout response */];
    $client = new MockHttpClient($responses);

    $response = $client->request('GET', '/test');

    $this->expectException(TimeoutException::class);
    $this->assertEquals(200, $response->getStatusCode());
}

My issue is that I cannot seem to find a way to produce a TimeoutException, I always end with a TransportException.

I tried with those responses:

$responses = [new class extends MockResponse { public function getStatusCode(): int { throw new TimeoutException(); } }];
$responses = [new MockResponse((static fn () => yield new ErrorChunk(0, 'Timeout1'))())];
$responses = [new MockResponse([new ErrorChunk(0, 'Timeout')])];

They all seem to give an error in their ErrorChunk::_destruct (or for an ErrorChunk that they produce, I'm not sure).

Interestingly if I remove the last assert this test pass (but in my code I cannot remove this assert because I have to check for the status code):

-    $this->assertEquals(200, $response->getStatusCode());
+    $response->getStatusCode();

Does anyone have a suggestion? Am I misunderstanding this? Is there an issue in MockResponse that I should report?