numpy.less_equal() in Python
Last Updated :
08 Mar, 2024
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The numpy.less_equal() function checks whether x1 is <= x2 or not.
Syntax :
Python
Output :
Python
Output :
Python
Output :
numpy.less_equal(x1, x2[, out])Parameters :
x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be
broadcastable to a common shape
out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.
Return :
Boolean array indicating results, whether x1 is lesser than x2 or not.Code 1 :
# Python Program illustrating
# numpy.less_equal() method
import numpy as geek
a = geek.less_equal([8., 2.], [5., 3.])
print("less_equal() : \n", a, "\n")
b = geek.less_equal([2, 2], [[1, 3],[1, 4]])
print("less_equal() : \n", b, "\n")
a = geek.array([4,3])
b = geek.array([6,2])
print("Is a less_equal than b : ", a <= b)
less_equal() : [False True] less_equal() : [[False True] [False True]] Is a less_equaler than b : [ True False]Code 2 :
# Python Program illustrating
# numpy.less_equal() method
import numpy as geek
# Here we will compare Complex values with the
a = geek.array([100j,7])
b = geek.array([1,2])
print("Comparing complex with int : ", a <= b)
d = geek.less_equal(a, b)
print("\n Comparing complex with int .less_equal() : ", d)
Comparing complex with int : [ True False] Comparing complex with int .less_equal() : [ True False]Code 3 :
# Python Program illustrating
# numpy.less_equal() method
import numpy as geek
# Here we will compare Float with int values
a = geek.array([1.1, 1])
b = geek.array([1, 2])
print("Comparing float with int : ", a <= b)
d = geek.less_equal(a, b)
print("\n Comparing float with int using .less_equal() : ", d)
Comparing float with int : [False True] Comparing float with int using .less_equal() : [False True]Note : These codes won’t run on online-ID. Please run them on your systems to explore the working.
